If equations of a projectile projected at angle θ with horizontal are followingx = 15t (m)y = 15t – 5t2 (m), (where x and y are co-ordinates) then angle of projection will be

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Questions Match

1.
If equations of a projectile projected at angle θ with horizontal are following
x = 15t (m)
y = 15t – 5t² (m), (where x and y are co-ordinates) then angle of projection will be

1. 30°2. 60°3. 45°4. 90°

2.
If equations of a projectile projected at angle θ with horizontal are following
x = 15t (m)
y = 15t – 5t² (m), (where x and y are co-ordinates) then the initial velocity is given by

1. 15 m/s2. m/s3. 30 m/s4. 20 m/s

3.
If equations of a projectile projected at angle θ with horizontal are following
x = 15t (m)
y = 15t – 5t² (m), (where x and y are co-ordinates) then time to reach maximum height taken by projectile will be

1. 1 second2. 1.5 seconds3. 2 seconds4. 3 seconds

4.
If equations of a projectile projected at angle θ with horizontal are following
x = 15t (m)
y = 15t – 5t² (m), (where x and y are co-ordinates) then, the speed of ball at maximum height of projectile is

1. 15 m/s2. m/s3. Zero4. 40 m/s

5.
If equations of a projectile projected at angle θ with horizontal are following
x = 15t (m)
y = 15t – 5t² (m), (where x and y are co-ordinates) then speed after 1 second of projection is

1. 15 m/s2. m/s3. 25 m/s4. 10 m/s

If equations of a projectile projected at angle θ with horizontal are followingx = 15t (m)y = 15t – 5t2 (m), (where x and y are co-ordinates) then angle of projection will be